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Shuffle Qiskit gate order?

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How do I generate a random quantum circuit with $n$ gates and $q$ qubits in Qiskit This is answered here ; basically, use random_circuit from qiskit.circuit.random . shuffle the order of the gates

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    Shuffle Qiskit gate order? Ask Question Asked 7 days ago Modified 5 days ago Viewed 122 times 1 How do I generate a random quantum circuit with n 𝑛 gates and q 𝑞 qubits in Qiskit This is answered here; basically, use random_circuit from qiskit.circuit.random. shuffle the order of the gates qiskitcircuit-constructionrandom-quantum-circuit Share Improve this question Follow edited Jun 21 at 6:05 Martin Vesely 15.6k4 4 gold badges 34 34 silver badges 77 77 bronze badges asked Jun 19 at 20:25 Geremia 1879 9 bronze badges Add a comment 2 Answers Sorted by: Highest score (default) Date modified (newest first) Date created (oldest first) 1 If you want to do it correct, not a naive approach, using exclusively Qiskit, you can mess a bit with the Qiskit transpiler. Basically, a circuit in Qiskit is represented as a DAG (Direct Acyclic Graph), where each gate is a node and the edges encode data dependencies between gates on the same qubit. So this is the correct way to shuffle it. If you just do random.shuffle(qc.data), you can generate invalid orderings (as placing a gate before another it depends on). The DAG prevents that, as it only lets you place a gate after all its dependencies are satisfied, so the shuffle is as random as physically possible while still producing a valid circuit. import random from qiskit import QuantumCircuit from qiskit.transpiler import PassManager from qiskit.transpiler.basepasses import TransformationPass class ShuffleGates(TransformationPass): def run(self, dag): nodes = list(dag.topological_op_nodes()) random.shuffle(nodes) new_dag = dag.copy_empty_like() for node in nodes: new_dag.apply_operation_back(node.op, node.qargs, node.cargs) return new_dag def shuffle_circuit(qc : QuantumCircuit) -> QuantumCircuit: pm = PassManager(ShuffleGates()) shuffled_qc = pm.run(qc) return shuffled_qc topological_op_nodes() gives you the gates in dependency order. Shuffling them and replaying onto a fresh DAG with apply_operation_back randomizes the order while respecting qubit dependencies. This was REALLY fun to solve. I work a lot these days with these things, but I had never thought of solving this problem. Hope this solution is valid to you. 🙂 Share Improve this answer Follow edited Jun 21 at 22:42 Geremia 1879 9 bronze badges answered Jun 21 at 13:35 Enrique Anguiano Vara 1265 5 bronze badges Your answer is interesting, but did the OP say that they wanted all dependencies maintained? You can take a circuit, shuffle the gates, and you'll still have a circuit, though most likely it won't do anything useful. Given the original question was about random circuits, it's unclear which question they were actually asking. –  Frank Yellin Commented Jun 21 at 17:23 1 @FrankYellin You're right but it can generate orderings that are invalid as measurement before a gate on the same qubit (i like weak-measurments but this is not the case) The DAG approach avoids that by only shuffling gates that are free to move. Whether the resulting circuit is meaningful is something idk, but at least it's legal. –  Enrique Anguiano Vara Commented Jun 21 at 17:36 What about simply reversing the order of the gates? Is the DAG method still necessary in that case? Or would ops.reverse() in my solution work? –  Geremia Commented Jun 21 at 19:51 1 @Geremia Yes, for reversing should work what you said (the method here, not the code below). Idk your goal with this but note qc.inverse() is a bit more general than qc.reverse_ops() if you want to make any complex gate become the identity. (as an example, a T gate, in reverse, you'll have TT≠I 𝑇 𝑇 ≠ 𝐼 but at inverse it will be for any gate). Nevertheless, note shuffling does not mean reversing by any meaning. Your solution below is doing a shuffling which can have illegal results as we discussed above –  Enrique Anguiano Vara Commented Jun 22 at 19:34 @EnriqueAnguianoVara Interesting. I didn't know about QuantumCircuit's reverse_ops() or inverse(). Gracias. 🙏 –  Geremia Commented Jun 22 at 20:00 Add a comment 1 This should work: import random def shuffle_gate_order(circ: QuantumCircuit, seed=None) -> QuantumCircuit: rng = random.Random(seed) new = QuantumCircuit(circ.num_qubits, circ.num_clbits) ops = list(circ.data) rng.shuffle(ops) for item in ops: inst = item.operation qargs = item.qubits cargs = item.clbits new.append(inst, qargs, cargs) return new Note: Reversibility of quantum circuits does not mean gate-order doesn't matter. See this example. Share Improve this answer Follow edited Jun 20 at 4:57 answered Jun 19 at 21:40 Geremia 1879 9 bronze badges Add a comment Your Answer Sign up or log in Sign up using Google Sign up using Email and Password Post as a guest Name Email Required, but never shown Post Your Answer By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy. Start asking to get answers Find the answer to your question by asking. Ask question Explore related questions qiskitcircuit-constructionrandom-quantum-circuit See similar questions with these tags. The Overflow Blog Code isn’t the only thing causing your production... Paging Charity! How can engineering leaders avoid becoming Bond... Featured on Meta Partnering with Communities to Modernize Policies & Norms Linked 2 How to make circuit for randomly selected gate? 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    Jun 19, 2026
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