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I would like to ask about the need of a low temperature for the operation of superconducting qubits. I know a superconducting qubit is made from basically a LC circuit and Josephson junction. So obviously, since Josephson junctions are made from superconducting materials, it needs a low temperature to function. However, as stated in the link ( Would an ambient-pressure, room-temperature superconductor eliminate the need for a dil-fridge in transmon processors? ), a low temperature is required no
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I would like to ask about the need of a low temperature for the operation of superconducting qubits. I know a superconducting qubit is made from basically a LC circuit and Josephson junction. So obviously, since Josephson junctions are made from superconducting materials, it needs a low temperature to function.
However, as stated in the link (Would an ambient-pressure, room-temperature superconductor eliminate the need for a dil-fridge in transmon processors?), a low temperature is required not only for it to be superconducting but for it to reduce noises and protect the qubits from collapsing.
Does this mean that superconducting qubits have relatively shorter coherence time and susceptible to noises compared to other qubits like photon based ones, which can be used at RT?
Also, relating to this, I am guessing that a low temperature is required to keep the system quantum like explained here (How do we know that a superconducting circuit is a quantum system?). Is this correct? The energy separation of superconducting qubits is relatively small corresponding to the microwave range, but can you engineer the energy separation? Why does the current qubit uses microwave not other optical region?
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asked Jan 3, 2024 at 13:55
Yukina
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Does this mean that superconducting qubits have relatively shorter coherence time and susceptible to noises compared to other qubits like photon based ones, which can be used at RT?
Yes, superconducting qubits are one of the lowest coherence times (SpinQuanta article. Pennylane, part of Xanadu, a photonics-based QC company, also has this explained in more detail Pennylane. An interesting consideration is that while operations on sc qubits are faster than other modalities (like trapped-ion),coherence times are shorter, exhibiting the tradeoffs between different qubit modalities.
Also, relating to this, I am guessing that a low temperature is required to keep the system quantum like explained here (How do we know that a superconducting circuit is a quantum system?). Is this correct? The energy separation of superconducting qubits is relatively small corresponding to the microwave range, but can you engineer the energy separation? Why does the current qubit uses microwave not other optical region?
Short answer, yes. Superconductivity, as you stated, requires extremely low temperatures. Sure, numbers like 15 mK sound low, but when you realize that is colder than negative four hundred degrees farenheit, I think that adds more scale. The exact energy separation can be engineered, to some extent, by device design, including the geometry of the circuit, capacitance, or inductance, and since the inherent properties of these qubits are in the microwave range, this is the primary means through which sc qubits have been engineered.
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answered Nov 12, 2025 at 21:23
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