Why is X/Z biased fault intolerance necessarily bad?

Why is X/Z biased fault intolerance necessarily bad? Ask Question Asked today Modified today Viewed 10 times 0 I need some help interpreting what a biased Stim logical error rate means in context. Suppose I have a fault tolerant gadget where the X observable has distance of d 𝑑 but the Z observable has a distance of d/2 𝑑 / 2 . Assume I have a normal rotated surface code without any noise biasing at the physical-qubit level. When I compile and run a quantum algorithm, what exactly would be the problem? Could the algorithm be compiled in a way that avoids the Z observable? Or is the fault tolerant gadget most likely to be useless? error-correctionstim Share Improve this question Follow asked 3 hours ago YoungProbopass 375 5 bronze badges Add a comment Know someone who can answer? Share a link to this question via email, Twitter, or Facebook. 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